prove that root 3 is an irrational number
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He bro root2 ko change krke root3 rakh do na
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Let us assume that root 3 is rational,
So root 3=a/b (where a and b are Co prime and have 1 as Hcf)
Squaring both sides,
3 = a2/b2
3b2=a2....(1)
a2/3=b2
So, a2 is divisible by 3 and so, a I also divisible by 3(by theorem)
Now,
a=3c
Squaring both sides,
a2=9c2
3b2=9c2(from eq. 1)
b2=3c2
b2/3=c2
so, b2 is divisible by 3 and hence b is also divisible by 3 (by theorem)
Now, we can conclude that a and b are divisible by 3 and 1 both... So they are not Co prime numbers.
Hence our assumption was wrong
Therefore, root 3 is irrational...
Hence proved
Hope it helps you dear.....
So root 3=a/b (where a and b are Co prime and have 1 as Hcf)
Squaring both sides,
3 = a2/b2
3b2=a2....(1)
a2/3=b2
So, a2 is divisible by 3 and so, a I also divisible by 3(by theorem)
Now,
a=3c
Squaring both sides,
a2=9c2
3b2=9c2(from eq. 1)
b2=3c2
b2/3=c2
so, b2 is divisible by 3 and hence b is also divisible by 3 (by theorem)
Now, we can conclude that a and b are divisible by 3 and 1 both... So they are not Co prime numbers.
Hence our assumption was wrong
Therefore, root 3 is irrational...
Hence proved
Hope it helps you dear.....
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