prove that root 3 is an irrational number.
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Answered by
6
HOLA!!!
Let us assume √3 as rational.
Therefore, √3=p/q
( √3)q=p
We can see that LHS is irrational whereas RHS is rational.
So, our preassumption is contradicted.
So, √3 is irrational.
HOPE IT HELPS UHH #CHEERS
Answered by
1
Assume root 3 is rational.It can be written as root3=p/q Where q is not equal to 0 and p and q are integers without common factor.
On squaring,
3=p^2/q^2
=>3q^2=p^2
therefore,3 divides p.
p=3k for some integer k.
p^2=9k^2 => 3q^2=9k^2 => q^2=3k^2
3 divides q^2 =>3 divides q.
Here p and q has common factor 3.therefore by method of contradiction,root 3 is irrational.
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