Prove that root 3 - root 2 is irrational.
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Step-by-step explanation:
let us assume, to the contrary that root3 is rational
√3=a/b
so b√3=a
squaring on both the sides therefor, a square is divisible by 3 and theorem 1.3 ,it follows that a is also divisible by 3
so we can write a=3c for some integer c
sabstituing for a
we get 3b square = 9c square that is b square =3c square
this means that b square is divisible by 3 ,and so b is also divisible by 3
therefore, a and b have least 3 as a common factor
but this show that a and b are coprime
this contradicts that our assumption is wrong that √3 ur rational
so we concluded that √3 Is irrational
same for √2 also
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