prove that root 5 -3 root 2 is irrational number
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Solution :)
Let,
and, its simplest form be a/b.
=> 5 -3 √2 = a/b
=> 3√2 =5-a/b
=>3√2 =(5b - a)/b
=> √2= (5b-a)/2b
Hence, a,b,5 and 2 are integers
therefore, (5b-a)/2b is also rational.
But, in fact, √2 is irrational.
Since, rational can't be equal to irrational.
Our assumption is wrong.
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