Question

Two years ago, father was three times as old as his son and two years hence, twice
is age will be equal to five times that of his son. Find their present ages.​

Answer 1

Hello dude ☺
Here is ur answer ✌

Let,
son's age 2 years ago be x years.
Then, father's age 2 years ago = (3x) years.
Therefore,
the son's age 2 years hence = ( x + 4 )
father's age 2 years hence = (3x + 4 )
According to the question
2(3x + 4) = 5(x + 4)
→ 6x + 8 = 5x + 20
→ x = 12
Son's age 2 years ago = 12 years
father's ages 2 years ago = 12 × 3 = 36 years
Therefore,
Son's present age = (12 + 2) = 14 years
fathers age = (36 + 2) = 38 years

Thankyou ☺☺

Answer 2

Answer:

Answer:son's present age 14 yrs and father's present age 38yrs