prove that root 5 is irrational
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by the contradiction method we can find it
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WE HAVE TO PROVE THAT ROOT 5 IS IRRATIONAL
LET US ASSUME THE OPPOSITE,
i.e ROOT 5 IS RATIONAL
HENCE ROOT 5 CAN BE WRITTEN IN THE FORM OF a|b
WHERE A AND B(B IS NOT EQUALS TO 0)ARE CO PRIME (NO COMMON FACTOR OTHER THAN 1
HENCE ROOT 5=A/B
ROOT 5B=A
SQUARING OB BOTH THE SIDES
(ROOT5B SQUARE)= A SQUARE
A SQUARE/5= B SQUARE
HENCE 5 DIVIDES A SQUARE
BY THE THEOREM :IF P IS A PRIME NUMBER AND DIVIDES A SQUARE,THEN P DIVIDES A, WHERE A IS A POSITIVE NUMBER.
SO, 5 SHALL DIVIDE A ALSO ....(1)
HENCE,WE CAN SAY
A/5=C WHERE C IS SOME INTEGER
SO, A =5C
NOW WE KNOW THAT 5B SQUARE =A SQUARE
PUTTING A=5C
5B SQUARE = (5C)SQUARE
5B SQUARE=25C SQUARE
B SQUARE=1/5*25C SQUARE
B SQUARE=5C SQUARE
BSQUARE/5 =C SQUARE
HENCE 5 DIVIDES B SQUARE
SO 5 DIVIDES B ALSO ....(2)
BY (1) AND (2)
5 DIVIDES BOTH A AND B
HENCE 5 IS A FACTOR OF A AND B
SO A AND B HAVE A FACTOR 5
THEREFORE, A AND B ARE NOT CO PRIME.
HENCE OUR ASSUMPTION IS WRONG
THIS CONTRADICTS THAT, ROOT 5 IS IRRATIONAL NO.
LET US ASSUME THE OPPOSITE,
i.e ROOT 5 IS RATIONAL
HENCE ROOT 5 CAN BE WRITTEN IN THE FORM OF a|b
WHERE A AND B(B IS NOT EQUALS TO 0)ARE CO PRIME (NO COMMON FACTOR OTHER THAN 1
HENCE ROOT 5=A/B
ROOT 5B=A
SQUARING OB BOTH THE SIDES
(ROOT5B SQUARE)= A SQUARE
A SQUARE/5= B SQUARE
HENCE 5 DIVIDES A SQUARE
BY THE THEOREM :IF P IS A PRIME NUMBER AND DIVIDES A SQUARE,THEN P DIVIDES A, WHERE A IS A POSITIVE NUMBER.
SO, 5 SHALL DIVIDE A ALSO ....(1)
HENCE,WE CAN SAY
A/5=C WHERE C IS SOME INTEGER
SO, A =5C
NOW WE KNOW THAT 5B SQUARE =A SQUARE
PUTTING A=5C
5B SQUARE = (5C)SQUARE
5B SQUARE=25C SQUARE
B SQUARE=1/5*25C SQUARE
B SQUARE=5C SQUARE
BSQUARE/5 =C SQUARE
HENCE 5 DIVIDES B SQUARE
SO 5 DIVIDES B ALSO ....(2)
BY (1) AND (2)
5 DIVIDES BOTH A AND B
HENCE 5 IS A FACTOR OF A AND B
SO A AND B HAVE A FACTOR 5
THEREFORE, A AND B ARE NOT CO PRIME.
HENCE OUR ASSUMPTION IS WRONG
THIS CONTRADICTS THAT, ROOT 5 IS IRRATIONAL NO.
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vaibhav183:
thanks
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