prove that root2+root7 is an irrational
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assume that root2+root7 is rational
√2+√7=p/q
squaring on both sides
(√2+√7)^2=(p/q)^2
√2^2+√7^2+2(√2)(√7)=p^2/q^2
2+2+2√14=p^2/q^2
4+2√14=p^2/q^2
2√14=p^2-4q^2/q^2
√14=p^2-4q^2/2q^2
Rhs side Al are rational no then √14is also rational
but this contradicts the fact that root 14 in irrational
therefore root2+root7 is irrational
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