Question

prove that root7-root5 is an irrational number FAST....​

Answer 1

Firstly we find the square root of 7 and 5 then square root of 7 is 2.6457513111..., hence we objerve it that the decimal representation of square root of 7 is neither terminating nor repeating.hence it is irrational number.

You can do the root of 5 similarly.
Please like it atlesast
or another way in the picture.