Prove that route P + route q is irrational where, p, q are primes.
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Answered by
19
Let us assume that P + √q is a rational number.
And a rational number can be written in the form of a / b where a & b are co - prime numbers .
p + √q = a/b
√q = ( a/b ) - p
√q = ( a - bp )/ b
Since ,√q is an irrational number and
( a - bp ) /b is a rational number.
And an irrational number can't be equal to a rational number.
So , Our assumption is wrong
p + √q is an irrational number.
And a rational number can be written in the form of a / b where a & b are co - prime numbers .
p + √q = a/b
√q = ( a/b ) - p
√q = ( a - bp )/ b
Since ,√q is an irrational number and
( a - bp ) /b is a rational number.
And an irrational number can't be equal to a rational number.
So , Our assumption is wrong
p + √q is an irrational number.
Answered by
4
Let as assume that p + √q is a rational no.
then,
p + √q = a/b
√q = a/b - p
√q = ( a - bp )/b
Since √q is irrational and ( a - bp )/b is a rational number...and irrational number and rational number can't be equal so our assumption is wrong.
p + √q is an irrational number.
then,
p + √q = a/b
√q = a/b - p
√q = ( a - bp )/b
Since √q is irrational and ( a - bp )/b is a rational number...and irrational number and rational number can't be equal so our assumption is wrong.
p + √q is an irrational number.
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