prove that Rs=R1+R2+R3........Rn
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consider three resistors R1, R2 and R3 are connected in series. Let I be the current flowing through and V1, V2 and V3 be the potential difference across he series combination.
if V1, V2 and V3 be the potential difference across R1, R2 and R3 respectively then
Vs = V1 + V2 + V3 ------------(1)
By Ohm's law
Vs = IRs --------------/(2)
V1 = IR1 --------------/(2)
V2 = IR2 ------------/(2)
V3 = IR3 -------------/(2)
Substituting (2) in (1) we get,
IRs = IR1 + IR2 + IR3
IRs = I (R1 + R2 + R3)
Rs = R1 + R2 + R3
Hence proved
consider three resistors R1, R2 and R3 are connected in series. Let I be the current flowing through and V1, V2 and V3 be the potential difference across he series combination.
if V1, V2 and V3 be the potential difference across R1, R2 and R3 respectively then
Vs = V1 + V2 + V3 ------------(1)
By Ohm's law
Vs = IRs --------------/(2)
V1 = IR1 --------------/(2)
V2 = IR2 ------------/(2)
V3 = IR3 -------------/(2)
Substituting (2) in (1) we get,
IRs = IR1 + IR2 + IR3
IRs = I (R1 + R2 + R3)
Rs = R1 + R2 + R3
Hence proved
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