prove that s=ut+1/2 at squre( use ananalytical method)
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Answer:
2nd equation of motion
Explanation:
s=area under the graph
s=area of rectangle +area of triangle
s=l×b + 1/2×b×h
s=u×t × 1/2 × t ×(v-u)
s= ut + 1/2 × t × at
s= ut + 1/2 at square
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Answer:
here is you answer
s=l×b + 1/2×b×h .=
s=u×t
s= ut + 1/2 × t × at
s= ut + 1/2 at square
s= ut + 1/2 at square
s= ut + 1/2 at square.
Explanation:
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