Question

Prove that:
sec^2 (90 -theta)-[1/cot^2(90-theta)]=1​

Answer 1

$\to \bold{ {sec}^{2} (90 - \theta) }- \bold{ \frac{1}{ {cot}^{2} (90 - \theta)}} \\ \\ \to \bold{ {cosec}^{2} \theta \: - } \bold{\frac{1}{ {tan}^{2} \theta} } \\ \\ \to \bold{ {cosec}^{2} \theta } - \bold{ {cot}^{2} \theta }\\ \\ \to \bold{ 1}$