Math, asked by anishservice12p825x0, 1 year ago

Prove That
Sec(270°-theta) Sec(90°-theta) - tan(270°-theta)tan(90°+theta) = -1

Answers

Answered by soh2
68
Hey dear here is ur answer *******
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sec(270°-theta) sec(90°- theta) -tan(270°- theta) tan(90°+ theta)

=sec(90°×3-theta) sec(90°×1-theta)-tan(90°×3-theta) tan(90°×1+theta)

=-cosec theta cosec theta-{cot theta ×(-cot theta)}

=-cosec^2 theta+cot^2 theta

=-1[Proved]

Hope it will help u@@@###

soh2: please mark my answer as brainliest
Answered by utcrush18
9

Answer:

Step-by-step explanation:

sec(270°-theta) sec(90°- theta) -tan(270°- theta) tan(90°+ theta)

=sec(90°×3-theta) sec(90°×1-theta)-tan(90°×3-theta) tan(90°×1+theta)

=-cosec theta cosec theta-{cot theta ×(-cot theta)}

=-cosec^2 theta+cot^2 theta

=-1[Proved]

Hope it will help u@@@###

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