Question

prove that sec^2x + cos^2x can never less than 2​

Answer 1

Step-by-step explanation:

Ans: S.T Sec2θ + Cosec2θ can never be less than 2. If possible let it be less than 2. 1 + Tan2θ + 1 + Cot2θ < 2. ⇒ (Tanθ + Cotθ)2 < 2.