Math, asked by hoodadarsyak7, 11 months ago

prove that sec^2x + cos^2x can never less than 2

Answers

Answered by deepalunthi878

2

Step-by-step explanation:

Ans: S.T Sec2θ + Cosec2θ can never be less than 2. If possible let it be less than 2. 1 + Tan2θ + 1 + Cot2θ < 2. ⇒ (Tanθ + Cotθ)2 < 2.

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