Question

Prove that sec A (1 - sin A)(sec A + tan A) = 1.​

Answer 1

Answer:

$\huge\star\underline{\orange{❥︎a}\mathfrak\blue{n}\mathfrak\purple{S}\mathbb\pink{wer}}\star\:$

L.H.S = secA (1−sinA) (secA+tanA) = $(secA - \frac{sinA}{cosA} )$

(secA+tanA)

=(secA−tanA) (secA+tanA)

=sec²A −tan²A

Putting if tan²A+1 = sec²A−

we get L.H.S = 1+tan²A − tan²A = 1

⇒L.H.S = R.H.S

Answer 2

Answer:

.H.S=secA(1−sinA)(secA+tanA)=(secA−cosAsinA)(secA+tanA)

=(secA−tanA)(secA+tanA)

=sec2A−tan2A

Putting if tan2A+1=sec2A−

we get L.H.S=1+tan2A−tan2A=1

⇒L.H.S=R.H.S

Step-by-step explanation:

make me brainlist

please give me some thanks