Prove that sec A (1 – sin A)(sec A + tan A) = 1
Class 10 - Trigonometric Identities
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Answer:
secA(1-sinA)(secA+tanA)
=secA-1bycosA.secA(secA+tanA)
=secA+tanA)(secA-tanA)
=sec^2A-tan^2A
=1
formula used
secA=1/cosA
tanA=sinA\cosA
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