Question

prove that (sec A + tan A) (1 - sin A) = cos A​

Answer 1

Step-by-step explanation:

[(secA+tanA)(1−sinA)]

⇒[(

cosA

1+sinA

)(1−sinA)]

⇒

cosA

1−sin

2

A

=

cosA

cos

2

A

⇒cosA

Hence, the answer is cosA.

Answer 2

Answer:

Step-by-step explanation:

$(sec A+tan A)(1-sinA)$

$=(1/cos A + sin A/cos A)(1-sinA)$

$=[(1+sinA)/cosA](1-sinA)\\=(1+sinA)(1-sinA)/cosA\\=(1-sin^2 A)/cosA\\=(cos^2 A)/cos A\\\\=cos A$

$Hence\:proved\\\\<Follow|ME>$