Question

prove that (sec X-tan X)^2 /sec X- tan X = 2sec X

Answer 1

Answer:

$= \frac{ {( \frac{1}{cos \: x} - \frac{sin \: x}{cos \: x} )}^{2} }{ \frac{1}{cos \: x} - \frac{sin \: x}{cos \: x} } \\ = {( \frac{1 - sin \: x}{cos \: x}) }$

Bhai the question is wrong