Prove that sec20 + cosec20 = tan 0 + cote
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Answer:
RHS
Step-by-step explanation:
LHS = tanO/(1-cotO) + cotO/(1-tanO)
=
= [1 +(1/cosecOsecO)]/[1/cosecOsecO]
=[(cosecOsecO+1)/cosecOsecO]*[cosecOsecO]
=cosecOsecO+1
=RHS
Hence proved
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