prove that (sec²A+cosec² A)=tanA+cota
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Answer:
I think the question is wrong
It should be like√sec²A+cosec²A=tanA+cot A
Step-by-step explanation:
This the answer
Taking LHs
√sec²A+cosec²A
√(1+tan2A)+(1+cot²a)
√1+tan²A+1+cot²A)
√tan²a+cot²a+2
√tan²A+cot²A+2 tanA.cotA
√(tanA+cotA)²
tan A+cotA
hence LHS=RHs
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