prove that sec²A-tan²A=1 by geometrical method
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To prove-: sec^2A-tan^2A=1
Solution-: 1/cos^2 - sin^2A/cos^2A=1
(secA=1/cosA and tan A =sinA/cosA)
1-sin^2A/cos^2A=1
cos^2A/cos^2A=1
1=1
LHS= RHS
Hence, sec^2A-tan^2A=1
Step-by-step explanation:
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