Prove that sec4 - sec2 = tan2 + tan4
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Answered by
84
Solution:-
sec⁴theta-sec²theta
sec²theta(sec²theta - 1) = (1+tan²theta){(1+tan²theta) - 1}
= (1+tan²theta)(tan²theta) = tan²theta + tan⁴theta⁴
sec⁴theta - sec²theta = tan²theta + tan⁴theta
proved.
sec⁴theta-sec²theta
sec²theta(sec²theta - 1) = (1+tan²theta){(1+tan²theta) - 1}
= (1+tan²theta)(tan²theta) = tan²theta + tan⁴theta⁴
sec⁴theta - sec²theta = tan²theta + tan⁴theta
proved.
Answered by
42
Answer:
Step-by-step explanation:
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