Prove that secA-1/sec+1=1-cosA/1+cosA
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L.H.S= (1/cosA-1)/1/cosA+1
= {(1-cosA)/cosA}/(1+cosA)/cosA
So cosA will be cutted from numerator as well as denominator
= 1-cosA / 1+cosA
I hope it will help you
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= {(1-cosA)/cosA}/(1+cosA)/cosA
So cosA will be cutted from numerator as well as denominator
= 1-cosA / 1+cosA
I hope it will help you
Please mark it as brainliest...
Thank you...
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