Prove that
secA(1 – sinA)(secA + tanA) =1
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
LHS= secA(1 – sinA)(secA + tanA)
= 1/ cosA (1- sinA)(1/cosA+sinA/cosA)
=1-sinA/cosA X 1+sinA/ cosA
=1-sin²A/cos²A
=cos²A/cos²A .........(sin²A+cos²A=1 ∴ cos²A = 1 - sin²A)
= 1
= RHS
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