Question

Prove that
secA(1 – sinA)(secA + tanA) =1​

Answer 1

Step-by-step explanation:

Hope you understand

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Answer 2

Answer:

Step-by-step explanation:

LHS=  secA(1 – sinA)(secA + tanA)

= 1/ cosA (1- sinA)(1/cosA+sinA/cosA)

=1-sinA/cosA X 1+sinA/ cosA

=1-sin²A/cos²A

=cos²A/cos²A       .........(sin²A+cos²A=1 ∴ cos²A = 1 - sin²A)

= 1

= RHS