prove that secA(1-sinA)(secA+tanA)=1
Answers
Answered by
0
Answer:
secA (1-sinA) (1/cosA + sinA/ cosA)
=secA(1-sinA) (1+sinA) /cosA
=1-sin²A/cos²A
=cos²A/cos²A
=1
Answered by
0
Step-by-step explanation:
Refer to the attachment
Hope it helps ☺️
Attachments:
Similar questions