Question

prove that :
(secA+tanA-1 )( secA -tanA +1 ) = 2 tanA

Answer 1

[secA+(tanA-1)(secA-(tanA-1)]

=sec²A-(tanA-1)²

=1/cos²A-(tan²A-2tanA+1)

=1+tan²A-tan²A+2tanA-1

=(1-1)tan²A-tan²A + 2tanA

=0+0+2tanA

=2tanA=2tanA

hence verified!

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Answer 2

Hello mate,

see this attachment,

hope it is helpful to you,

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