Question

prove that
secsqure teta minus tansqureteta is equal to 1​

Answer 1

Answer:

I'll use x instead of θ.

Sec²x - tan²x = 1

LHS ⇒ Sec²x - Tan²x

= (h/b)² - (p/b)²

= h²/b² - p²/b²

= h² - p²/ b²

by pythagorus theorum, h²-p²=b²

= b² / b²

= 1  = RHS

HENCE, PROVED.

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