Question

Prove that sigma(xi-x(bar))=0
("i" is subscript).
please give an answer with clear explanations..

Answer 1

$\Sigma_{i=0}^{n}\ [ x_i - \bar{x }]\\\\=\Sigma_{i=0}^n\ x_i \ - \Sigma_{i=0}^n\ \bar{x}\\\\=n * \bar{x}-\bar{x}\ *\ \Sigma_{i=0}^n\ 1,\ \ \ as\ \bar{x}\ same\ for\ all\ i\\\\=n*\bar{x}-\bar{x}*n\\\\=0$

Answer 2

here is your correct answer