Question

Prove that:
(sin 0 + 1 + cos 0) (sin 0 - 1 + cos 0). sec 0 cosec 0 = 2​

Answer 1

Hey there

Here is your answer attached,

Answer 2

Answer:

Hey,,

Step-by-step explanation:

sin0=0 = cosec0= infinity

cos0=1 =sec0

let us use them in solving

well

1st 2 is of the form (a+b)(a-b)

{sin²0-(1+cos0)²}(sec 0.cosec0)

(0-1+1+2)(0)

0

:/