Question

Prove that:
(sin 0 + cos 0) (tan 0 + cot 0) = sec 0 + cosec 0​

Answer 1

Step-by-step explanation:

( sin0+ cos0) (sin0/cos0 + cos0/sin0)

(sin0+cos0) ( sin^2 0 +cos^2 0/sin 0×cos 0)

(sin0 + cos0) (1/sin0×cos0) = lhs

rhs= 1/cos0 +1/sin0

= sin0+ cos0/sin0 ×cos0

or

(sin0+cos0) (1/sin0×cos0)

Answer 2

Step-by-step explanation:

(sin 0+cos0)(sin0/cos0 +cos0/sin0)

(sin0+cos0)(sin2 0+cos2 0/sin0 cos0)

sin2 0+cos2 0=1

(sin0+cos0)(1/sin0 cos0)

sin0/sin0 cos0+cos0/sin0 cos0

1/cos 0+1/sin0

sec0+cosec0