Prove that sin-1(5/13)+cos-1(4/5) =1/2 sin- (3626/4223)
Answers
Answered
Prove that : sin^-1(5/13) + cos^-1(4/5) =1/2sin^-1(3696/4225)
2
SEE ANSWERS
abhi178
abhi178
we have to prove sin^-1(5/13) + cos^-1(4/5) = 1/2 sin^-1(3696/4225)
or, 2sin^-1(5/13) + 2cos^-1(4/5) = sin^-1(3696/4225)
let sin^-1(5/13) = x
so, sinx = 5/13 , cosx = 12/13
we know, sin2x = 2sinx.cosx
= 2 × 5/13 × 12/13 = 120/169
and cos2x = 1 - 2sin²x = 1 - 2 × (5/13)²
= (169 - 50)/169 = 119/169
similarly, cos^-1(4/5) = y
cosy = 4/5 , siny = 3/5
sin2y = 2 × 4/5 × 3/5 = 24/25
cos2y = 1 - 2(3/5)² = 7/25
now, sin(2x + 2y) = sin2x.cos2y + cos2x.sin2y
= 120/169 × 7/25 + 119/169 × 24/25
= (840 + 2856)/4225
= 3696/4225
hence, sin(2x + 2y) = 3696/4225
or, 2x + 2y = sin^-1(3696/4225)
now, LHS = 2sin^-1(5/13) + 2cos^-1(4/5)
= 2x + 2y
= sin^-1(3696/4225) = RHS
hence, it is proved that 2sin^-1(5/13) + 2cos^-1(4/5) = sin^-1(3696/4225)
so, it is also proved that sin^-1(5/13) + cos^-1(4/5) = 1/2sin^-1(3696/4225)