Question

prove that
sin^2 6x-sin^2 4x = sin2xsin10

Answer 1

you can see your answer

Answer 2

Given,

$\sin^{2}6x - \sin^{2}4x\\\;\\=\sin(6x+4x).\sin(6x-4x)\\\;\\=\sin10x.\sin2x\\\;\\\textbf{Formula:-}\\\;\\\;\sin^{2}A-sin^{2}B=\sin(A+B).\sin(A-B)$