prove that sin 2x=2sinx.cosx
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Step-by-step explanation:
Assume that sin(2x) = sin(x + x)
From trigonometry,
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
Similarly,
sin(x + x) = sin(x)cos(x) + cos(x)sin(x),
sin(x + x) = sin(x)cos(x) + sin(x)cos(x)
therefore,
sin(x + x) = sin(2x) = 2sin(x)cos(x
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