Question

prove that sin^(3/5)+ tan^(3/5)=tan^(27/11)​

Answer 1

Step-by-step explanation:

Answer:

Please see the explanations below.

Explanation:

Let

θ

1

=

cos

−

1

(

4

5

)

and

θ

2

=

tan

−

1

(

3

5

)

Therefore,

cos

θ

1

=

4

5

,

⇒

,

tan

θ

1

=

3

4

and

tan

θ

2

=

3

5

The equation is

θ

1

+

θ

2

=

tan

−

1

(

27

11

)

Let's calculate

tan

(

θ

1

+

θ

2

)

=

tan

θ

1

+

tan

θ

2

1

−

tan

θ

1

tan

θ

2

Therefore,

tan

(

θ

1

+

tan

θ

2

)

=

3

4

+

3

5

1

−

3

4

⋅

3

5

=

27

20

11

20

=

27

11

Finally,cos^-1(4/5)+tan^-1(3/5)=tan^-1(27/11)