prove that sin 4 theta + cos 4 theta upon 1 minus 2 sin square theta cos square theta is equal to
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abhishekalkari11:
No bro I didnot understand
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LHS
sin^4@ +Cos^4@ /(1- 2Sin^[email protected]^2@)
(Sin^2@)^2 +(Cos^2@)^2 /(1- 2Sin^[email protected]^2@)
=(Sin^2@ +Cos^2@)^2 -2Sin^[email protected]^2@/(.......)
=(1)^2 -2Sin^[email protected]^2@ / (1-2Sin^[email protected]^@)
=(1-2Sin^[email protected]^2@)/( 1-2Sin^[email protected]^@)
=1
LHS = RHS proved
________Formula used_____________
1st
(a)^2 +(b)^2
=( a+b)^2 -2ab
2nd
Sin^2@+ Cos^2@ =1
3rd
X÷X= 1
sin^4@ +Cos^4@ /(1- 2Sin^[email protected]^2@)
(Sin^2@)^2 +(Cos^2@)^2 /(1- 2Sin^[email protected]^2@)
=(Sin^2@ +Cos^2@)^2 -2Sin^[email protected]^2@/(.......)
=(1)^2 -2Sin^[email protected]^2@ / (1-2Sin^[email protected]^@)
=(1-2Sin^[email protected]^2@)/( 1-2Sin^[email protected]^@)
=1
LHS = RHS proved
________Formula used_____________
1st
(a)^2 +(b)^2
=( a+b)^2 -2ab
2nd
Sin^2@+ Cos^2@ =1
3rd
X÷X= 1
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