Prove that Sin(π/4+x)sin(π/4-x)=1/2cos2x
Answers
Answered by
9
we have sin(a+b)sin(a-b)
=sin²a-sin²b
A/Q;
Sin(pie/4+x+pie/4-x)sin(pie/4+x-pie/4+x)
sin(pie/2)sin2x
=sin²a-sin²b
A/Q;
Sin(pie/4+x+pie/4-x)sin(pie/4+x-pie/4+x)
sin(pie/2)sin2x
Answered by
7
Step-by-step explanation:
Sin(π/4+x)sin(π/4-x)
=1/2(2Sin(π/4+x)sin(π/4-x))
=1/2*[cos(π/4-x-π/4-x)/2+cos(π/4-x+π/4+x)
=1/2[cos(-2x)+cos(π/4+π/4)]
=1/2 [cos2x+0]
=1/2 cos2x
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