prove that
sin(50+A)cos(40-B)+cos(50+A)sin(40-b)=cos(A-B)
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Answer:
sin(90-50) sin 40 + cos (90-50) cos 40
sin40 sin40 + cos40 cos40
sin^2 40 + cos^2 40
(since sin @ + cos@ =1)
so sin^2 40 + cos^2 40 = 1
Step-by-step explanation:
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