Question

Prove that sin^6 + cos^6 + 3sin^2 cos^2 = 1
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Answer 1

Step-by-step explanation:

formula used

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab)$

${a}^{2} + {b}^{2} = {(a + b)}^{2} - 2ab$

${sin}^{2} \alpha + {cos}^{2} \alpha = 1$

Hope you will understand