Question

prove that sin 60 =3root /2​

Answer 1

Answer:

$\sin(60) = 3 \sqrt{2}$

$draw \: a \: perpendicular \: ad \: from \: a \: to \: the \: side \: bc \: \\ abd \: = \: adc \: \\ bd \: = \: dc$

$abd \: is \: a \: right \: angled \: at \: d \: with \: bad = 30 \: nd \: abd \: = \: 60 \: degree$

$bd = \frac{1}{2} bc = \: a \\ ad = ab - bd = {2a} \: - {a} \: = \: 3a$

$ad \: = \sqrt[a]{3}$

similarly...

$\sin(60) = \frac{a}{d} = \frac{a \sqrt{3} }{2a} = \frac{ \sqrt{3} }{2}$

$hence \: proved$

hope it helps you