prove that sin 60 in geometrically
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First take a 60-60-60 triangle, arm length of 2unit.
then from the vertex, Devide the triangle into two equal parts, So two angle will be formed of 30-90-60 & arms will be 2-1-root(3)
Now apply sine formula as
SIN THEETA = P/H
Sin(30) = 1/2
then from the vertex, Devide the triangle into two equal parts, So two angle will be formed of 30-90-60 & arms will be 2-1-root(3)
Now apply sine formula as
SIN THEETA = P/H
Sin(30) = 1/2
yash510:
plz solve it
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this is given in R.D. Sharma on Page no.5.29
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