prove that sin 7A-sin 5A÷cos 7A+cos 5A=tan A
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sin7A-sin5A=2(sin(7A-5A)÷2.cos(7A+5A)÷2)=2sinA.cos6A
cos7A+cos5A=2(cos(7A+5A)÷2.cos(7A-5A)÷2)=2cosA.cos6A
sin7A-sin5A÷cos7A+Cos5A=(2sinA.cos6A)÷(2cosA.Cos6A)=tanA
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