prove that (sin 7theta-sin theta) /(sin 8theta - sin 2theta) =cos 4 theta * sec 5 theta
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10
Given : sin7θ=cos2θ
⟹sin7θ=sin(90o−2θ)
⟹7θ=90o−2θ
⟹9θ=90o
⟹θ=10o
Hence, the answer is 10
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