Question

prove that sin (90 - A) cos (90 - A) /tan A =1-sin^2A
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Answer 1

Answer:

Step-by-step explanation:

cos(90 - A) = sinA

sin(90-A) = cosA

(sinA cosA)/tanA

===> (sinA cosA )/(sinA/cosA) ===> cos²A ===> 1 - sin²A

Answer 2

$\huge \bold{hey \: there}$

We know that

➡sin(90-A)=cosA

➡cos(90-A)=sinA

Now,

➡cosA.sinA/tanA

➡cosA.sinA/sinA/cosA

➡cosA.sinA×cosA/sinA

➡cos²A

We have an identity:

↪sin²A+cos²A=1

↪cos²A=1-sin²A

Therefore,

↪cos²A=1-sin²A

LHS=RHS