Prove that (sin A/1+cos A)+(sinA/1-cosA)=√1+cosA/1-cos A+√1-cosA/1+cos A=2 cosec A
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(SinA/1+cosA)+(SinA/1-cosA)
(sinA=2sinA/2.2cosA/2)
= 2sinA/2.cosA/2/2cossquareA/2+ 2sinA/2.cosA/2/2sinsquareA/2
=sinA/2/cosA/2+cosA/2/sinA/2
=sinsquareA/2+cossquareA/2/cosA/2.sinA/2
=1/cosA/2.sinA/2
multiplying and dividing with"2”.
=2/2sinA/2.cosA/2
=2cosecA
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here is your answer
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