Question

PROVE THAT : sin(A-45)° = 1/√2 × (sin A - cos A)​

Answer 1

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$\sin(A - 45) \\ = sinAcos45 - cosAsin45 \\ = sinA \frac{1}{ \sqrt{2} } - cosA \frac{1}{ \sqrt{2} } \\ = \frac{1}{ \sqrt{2} } (sinA - cosA)$