prove that
Sin A - Cos A + 1/ __1___
Sin A + Cos A- 1. == SecA-Tan A
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Step-by-step explanation:
sinA-cosA+1/sinA+cosA-1
devided by cosA in each term
tanA-1+secA/tanA+1-secA
={(tanA+secA)-1}(tanA-secA)/ (tanA-secA+1)(tana-secA)
=tan²A-sec²A-tanA+secA/(tanA-secA+1)(tanA-secA)
=-1-tanA+secA/(tanA-secA+1)(tanA-secA)
=-(1+tanA-secA)/(tanA-secA+1)(tanA-secA)
=-1/tanA-secA
=1/secA-tanA
=secA-tanA/sec²A-tan²A
=secA-tanA
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