prove that sin^A+cos^A=1
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As we know that,
In a right angled triangle,
sin A = Perpendicular/ Hypotenuse
And, cos A = Base / Hypotenuse
Now,
sin ^2 A + Cos^2 A = (P/H)^2 +(B/H)^2
= (P^2 + B^2)/H^2
We know, from Pythagoras theorem,
P^2 + B^2 = H^2. So,
= H^2 /H^2 = 1 ....Proved
Hope you will find it helpful.....
MARK IT AS BRAINLIEST.
In a right angled triangle,
sin A = Perpendicular/ Hypotenuse
And, cos A = Base / Hypotenuse
Now,
sin ^2 A + Cos^2 A = (P/H)^2 +(B/H)^2
= (P^2 + B^2)/H^2
We know, from Pythagoras theorem,
P^2 + B^2 = H^2. So,
= H^2 /H^2 = 1 ....Proved
Hope you will find it helpful.....
MARK IT AS BRAINLIEST.
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