Prove that : ( sin A + cos A )2 + ( sin A – cos A )2 = 2
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Answer:
L.H.S= (sin A + cos A )^2+ (sin A - cos A )^2
= sin² A + 2sinA.cosA + cos² A + sin² A - 2sinA.cosA + cos² A
= sin² A + cos² A + sin² A + cos² A
= 1 + 1
= 2
= R.H.S proved
Step-by-step explanation:
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