Math, asked by vbbharath01, 6 months ago

Prove that (sin A+ Cosec A) ² (COSA + soc A)²=7+ tan^2+ A + cot^2A

Answers

Answered by sonuchauhan8810
1

Answer:

helo guys its your answer

Step-by-step explanation:

(sin A + cosec A)^2 + (cos A + sec A)^2 = 7 + tan^2 A + cot^2A .) Las medidas de dos de los ángulos de un triángulo ABC son Â= 40° y = 1,54 rad. Calcula en grados y en radianes la medida de ĉ.

Pe

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