Question

prove that Sin A + cosec a whole square + Cos A + sec a whole square equals to 7 tan square A + cot square A

Answer 1

may be the answer is right

Answer 2

Answer:

Step-by-step explanation:

The given equation is:

$(sinA+cosecA)^{2}+(cosA+secA)^{2}$

=$sin^{2}A+cosec^{2}A+2sinAcosecA+cos^{2}A+sec^{2}A+2cosAsecA$

=$1+cosec^{2}A+sec^{2}A+2+2$  (Using $cosA=\frac{1}{secA}$ and $sinA=\frac{1}{cosecA}$)

=$5+(1+tan^{2}A)+(1+cot^{2}A)$

=$7+tan^{2}A+cot^{2}A$

Hence proved.